Question

If x2+kx+k=0 has no solution. then the value of k will satisfly.

यदि x2+ke+k=0 के कई हल नहीं है तो K का मान क्या होगा

Answer 1

Answer:

0 < k <4

Step-by-step explanation:

desriminant = b^2 - 4ac = ∆

∆ = k^2 - 4k <0

k(k-4) <0

means ...k > 0 or k < 4

hence 0 < k <4