Question

If x2 + xy + y3 = 1, find the value of y''' at the point where x = 1.

Answer 1

Answer:

y = -1

4

Step-by-step explanation:

x2+xy+y3=1. (if x is 1)

1×2+1×y+y×3=1

2+y+3y=1. (put 2 to another side)

y+3y=1-2. add 3y and y,subtract1-2 )

4y=-1

y=-1 or y= (4)power -1

4

Answer 2

Given:

x² + xy + y³ = 1

x = 1

To find:

The value of y at the point where x = 1.

Solution:

If x² + xy + y³ = 1

We can find the value of y at the point where x = 1 by substituting the value of x in the given equation.

Therefore,

x² + xy + y³ = 1

Substitute x = 1,

1² + (1)y + y³ = 1

1 + y + y³ = 1

y + y³ = 1 - 1

y + y³ = 0

y ( 1 + y²) = 0

1 + y² = 0

y² = -1

y = $\sqrt{-1}$

Final answer:

The value of y at the point where x = 1 is $\sqrt{-1}$