If x2+y2=10xy prove that 2 log( x + y)=logx+logy+2 log2 + log3
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Solution :
- Given : x² + y² = 10xy
- To prove : 2log(x + y) = logx + logy + 2log2 + log3
Proof :
We have ;
x² + y² = 10xy
Now ,
Adding 2xy both the sides , we get ;
=> x² + y² + 2xy = 10xy + 2xy
=> (x + y)² = 12xy
=> (x + y)² = 2²·3xy
Now ,
Taking log both the sides , we get ;
=> log[(x+y)²] = log[2²·3xy]
=> 2log(x+y) = log(2²) + log3 + logx + logy
=> 2log(x+y) = 2log2 + log3 + logx + logy
=> 2log(x+y) = logx + logy + 2log2 + log3
Hence proved .
Properties used :
• log(ab) = loga + logb
• log(a/b) = loga - logb
• logaⁿ = n·loga
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