Question

if x2+y2=12xy then show that 2log(x+y)=log2+log7+logx+logy​

Answer 1

Step-by-step explanation:

$2log(x + y) = log2 + log7 + logx + logy \\ log(x + y)^{2} = log(2 \times 7 \times x \times y) \\ (x + y)^{2} = 14xy \\ {x}^{2} + 2xy + {y}^{2} = 14xy \\ {x}^{2} + {y}^{2} = 14xy - 2xy \\ {x}^{2} + {y}^{2} = 12xy$