Question

if x²+y²=18xy, then find the value of 2log(x-y) in terms of log2,logx and logy

Answer 1

$2\log(x-y)\\~\\=\log(x-y)^2\\~\\=\log(x^2+y^2-2xy)\\~\\=\log(18xy-2xy)\\~\\=\log(16xy)\\~\\=\log(16)+\log(x)+\log(y)\\~\\=4\log(2)+\log(x)+\log(y)$

Answer 2

Answer:

see the pic

Step-by-step explanation:

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