Question

if x²+y²=20 and x²+3xy=28. find the value of x and y.​

Answer 1

Answer:

After simplification x= 2, y= 4 for confirmation substitute values in above equation

Explanation:

From equation x^2+3xy=28

we get y=(28-x^2)/3x

sub above equation in x^2+y^2=20

then x^2+((28-x^2)/3x)^2=20

after simplification

we get equation : 5x^4-118x^2+392=0

then we get x=2

sub in equation x^2+y^2=20

we get y = 4