Question

If x2+y2 = 25 and xy = 8 , find x-y.​​

Answer 1

Answer:

We know that,

${(x - y)}^{2} = {x}^{2} + {y}^{2} - 2xy \\ = 25 - 2 \times 8 \\ = 25 - 16 \\ = 9 \\ (x - y) = \sqrt{9} \\ = 3$

Step-by-step explanation:

Please mark as BRAINLIST AND FOLLOW ME ✌️ ✌️

Answer 2

The value of x -y is 3.

Given:

${x}^{2} + {y}^{2} = 25 \: and \: xy = 8$

To Find:

The value of x-y.

Solution:

To fund the value of x-y we will follow the following steps:

As we know,

According to the property:

${(x - y)}^{2} = {x}^{2} + {y}^{2} - 2xy$

Also,

According to the question:

xy = 8

And,

${x}^{2} + {y}^{2} = 25$

Now,

In putting values we get,

${(x - y)}^{2} = 25 - 2 \times 8 = 25 - 16 = 9$

${(x - y)}^{2} =9$

$x - y = \sqrt{9} = 3$

Henceforth, the value of x -y is 3.

#SPJ2