if x2+y2 =49and x-y=3 then find the value of x3-y3
Answers
Answered by
97
ANSWER:
______________________
Given that,
x2+y2=49
x-y=3
We Know That,
(x-y)^2=x2-2xy+y2
=>3^2 =49-2xy
=>9=49-2xy
=>49-2xy=9
=>-2xy=9-49
=>-2xy= - 40
=>xy = -40 ÷ (-2)
=>xy = 20
By Putting the Value of x3-y3,
We get
x3-y3
=(x-y)(x2+y2+xy)
=3(49+xy)
=3×49+20
=3×69
= 207 (Ans)
__________________________
Hope this is correct and Useful for you.
Thanks.
______________________
Given that,
x2+y2=49
x-y=3
We Know That,
(x-y)^2=x2-2xy+y2
=>3^2 =49-2xy
=>9=49-2xy
=>49-2xy=9
=>-2xy=9-49
=>-2xy= - 40
=>xy = -40 ÷ (-2)
=>xy = 20
By Putting the Value of x3-y3,
We get
x3-y3
=(x-y)(x2+y2+xy)
=3(49+xy)
=3×49+20
=3×69
= 207 (Ans)
__________________________
Hope this is correct and Useful for you.
Thanks.
Subhalaxmi72:
which class u 2 r ??
oohk
Iam of 10 class
ooh
Which class are you?
9th
Ok
Did get the answer
yes
pls mark as brainlist answer
Answered by
31
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how 3+y+y=7 ???
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