If x² + y2 = 6xy, prove that 2 log (x + y) = logx +logy + 3 log 2
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Step-by-step explanation:
It's given,
x²+y²=6xy
or,(x+y)²-2xy=6xy
=) (x+y)²=8xy
Taking log on both sides we get,
=)log(x+y)²=log2³xy
=)2log(x+y)=3log2+logxy
=)2log(x+y)=logx+logy+3log2
Hence proved,
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