Question

If x²+y²=73 and xy=24, what is (x-y)²​

Answer 1

Step-by-step explanation:

given,

x^2+y^2=73

xy=24

to find (x^2-y^2)

we know that

$a ^{2} - b ^{2} = a ^{2} + b ^{2} - 2ab$

by using the identity,

$(x ^{2} - y ^{2}) = x ^{2} + y ^{2} - 2xy$

(x^2-y^2)=73-2×24

(x^2-y^2)=73-48

(x^2-y^2)=25

so,

$x ^{2} - y ^{2} = 25$

Answer 2

Answer:

25

Step-by-step explanation:

Given :

x²+y²=73 ; xy=24

To find :

(x-y)²​

Solution :

We know that,

$\boxed{\mathrm{(x-y)^2 = x^2 - 2xy + y^2}}$

So, applying the values, we get

(x-y)²​ = x²+y² - 2xy

=> 73 - 2(24)

=> 73 - 48

=> 25

Hope it helps!