Question

if x²+y²=z+1; y²+z²=x+1 and z²+x²=y+1 then the value of xyz will be?​

Answer 1

Answer:

Squaring both sides

(x+y+z)

2

=x

2

+y

2

+z

2

+2(xy+yz+zx)

we can substitute given values

(x+y+z)

2

=18+(2×9)

(x+y+z)

2

=36

(x+y+z)=6