if x²+y²+z²=16and xy +yz+zx=10 then find the value of (x+y+z)
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Answered by
10
Answer:
6
Step-by-step explanation:
GIVEN
x²+y²+z²=16
xy +yz+zx=10
We know that
(x+y+z)^2 = x²+y²+z²+2* ( xy +yz+zx)
Now ,
(x+y+z)^2 = 16 + 2*10
(x+y+z)^2 = 36
(x+y+z) = 6
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3
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