Math, asked by Prabalpratap7373, 1 year ago

if x²+y²+z²=16and xy +yz+zx=10 then find the value of (x+y+z)

Answers

Answered by naveen1501
10

Answer:

6

Step-by-step explanation:

GIVEN

x²+y²+z²=16

xy +yz+zx=10

We know that

(x+y+z)^2 = x²+y²+z²+2* ( xy +yz+zx)

Now ,

(x+y+z)^2 = 16 + 2*10

(x+y+z)^2 = 36

(x+y+z) = 6

Answered by lata40386
3

Answer:

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