If x2 + y2 + z2 = 20 and x + y + z = 0, then xy + yz + zx is equal to :
Answers
Answered by
15
Hi friend
--------------
Your answer
-------------------
Given that : - (x² + y² + z²) = 20 and (x + y + z) = 0
To find : - Value of (xy + yz + zx) .
Now,
---------
We know that ,
------------------------
(x + y + z)² = (x² + y² + z²) + 2(xy + yz + zx)
Now, putting the values , we get,
(0)² = 20 + 2 (xy + yz + zx)
=> 2(xy + yz + zx) = 0 - 20
=> (xy + yz + zx ) = - 20/2
=> xy + yz + zx = - 10
HOPE IT HELPS
--------------
Your answer
-------------------
Given that : - (x² + y² + z²) = 20 and (x + y + z) = 0
To find : - Value of (xy + yz + zx) .
Now,
---------
We know that ,
------------------------
(x + y + z)² = (x² + y² + z²) + 2(xy + yz + zx)
Now, putting the values , we get,
(0)² = 20 + 2 (xy + yz + zx)
=> 2(xy + yz + zx) = 0 - 20
=> (xy + yz + zx ) = - 20/2
=> xy + yz + zx = - 10
HOPE IT HELPS
Similar questions