Math, asked by sourabhsenger473, 1 year ago

If x²+y²+z²-4x-8y-6z+ 29=o then find the value of (x/z+y/z)

Answers

Answered by Harsh336333
2
Final answer of your asked question is 2
Attachments:
Answered by rahulvimal133
0

Answer: 2

Step-by-step explanation:

X2 + Y2 + Z2 - 4X - 8Y - 6Z + 29 = 0.

Here each term is positive, so each term must be zero to get the sum as zero

So, x-2=0; y-4=0; z-3=0

x=2; y=4 and z=3

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