If x3+1/x3=110 find x+1/x
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x3+1/x3=110
(x+1/x)3=x3+1/x3+3x+1/x)
(x+1/x)3=110+3(x+1/x)
let (x+1/x)=a eq..1 so,
a3=110+3a
a3-3a-110
p(a)=a3-3a-110
put a=5
1st factor =(a-5)
p(5)=(5)3-3(5)-110=125-15-110
125-125=0
p(5)=0
(x+1/x)3=x3+1/x3+3x+1/x)
(x+1/x)3=110+3(x+1/x)
let (x+1/x)=a eq..1 so,
a3=110+3a
a3-3a-110
p(a)=a3-3a-110
put a=5
1st factor =(a-5)
p(5)=(5)3-3(5)-110=125-15-110
125-125=0
p(5)=0
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