Question

if x³+1/x³ =110, then x+1/x= ​

Answer 1

Answer:

Step-by-step explanation:

x3+1/x3=110

(x+1/x)3=x3+1/x3+3 (x+1/x)

(x+1/x)3=110+3 (x+1/x)

Let(x+1/x)=a eq … 1 So,

a3=110+3a

a3-3a-110=0

P (a)=a3-3a-110

PUT a=5

P (5)=(5)3-3 (5)-110=125-15-110

125-125=0

P (5)=0

1st factor =(a-5)

Write (a-5) three times and put the value according to polynomial

a2(a-5)+5a(a-5)+22(a-5)

(a-5)(a2+5a+22)

If (a-5)=0 or (a2+5a+22)=0

(a-5)=>x+1/x-5=0 from eq1

x+1/x=5 answer

NOTE =EVERY 3 is cube and some 2 is square in last steps after variable

Answer 2

Answer:

bp=bq=3

and pa=ra=4

rc=ac-ra

rc= 11 - 3

rc = 7

qc = rc = 7

qc + bq = 3 + 7 = 10