if x³–3x²+4x–4 is a polynomial, then one of it's a, x–1 b, x+1 c, x–2 d, x+
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i don't understand your question please explain a little bit more
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Step-by-step explanation:
using factor theoram if we divide f(x) then if the remainder is 0 it is a factor of f(x)
so if we take x+1
let us find the reminder if we divide f(x)with x+1
f(-1)= (-1)^3 - 3(-1)^2 +4(-1) -4
=-1-3-4-4
= -12
let us take x-1
f(1)= 1^3 - 3*1^2 +4(1)+4
=1-3+4-4
= -2
let us try
x-2
f(2)= 8 - 12 + 8 -4
=16-16
=0
so the answer is c, x-2
I used trail and error metod , remainder theoram and factor theoram as you can see
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