If x3 -5x2 - px +24 = (x-4).q(x), then what is the value of p?
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Step-by-step explanation:
remainder theorem:
dividend =divisors X quotient + remainder
therefore, let f (X)=x^3 +(kx +8)x + k
=x^3 + kx x^2+8x+k
Dividing if(X) by x+1 gives remainder as R 1
therefore f(-1)=R 1
also ,f(2) =R 2
therefore f(-1)=(-1)^3+k(_1) ^2+8(-1)+ k
=-1 +k-8+k
=2k-9= R 1
f(2)=(2)^3 + k(2) ^3 +8 X 2 + k
=8+4K+ 16 +K
=5k + 24 =R 2
also, sum of remainders=R1+R1=1
therefore,(2k-9)+(5k+ 24) = 1
7 k+ 15 =1
7k=-14
k =-2
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