If x3-6x2+6x +k is completely divisible by x-3 then find the value of k.answer this question by showing division
Answers
Answered by
2
x-3 ) x3-6x2=6x+k ( x2-3x-3
0
k = 9
Answered by
3
Answer:
k = 9
Step by Step Solution:
Given that ( X -3) is a factor of the given polynomial.
So,
( X-3) = 0
X = 3
P(X) = X³ -6X² + 6X + k
P(3) = (3)³ - 6 × (3)² + 6 × 3 + K
=> 27 - 6 × 9 + 18 + K
=> 27 - 54 + 18 + K = 0
=> 45 -54 + K = 0
=> K -9 = 0
=> K = 9
HOPE IT WILL HELP YOU....
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