Question

If x3-6x2+6x +k is completely divisible by x-3 then find the value of k.answer this question by showing division

Answer 1

x-3 ) x3-6x2=6x+k ( x2-3x-3

        0

k = 9

Answer 2

Answer:

k = 9

Step by Step Solution:

Given that ( X -3) is a factor of the given polynomial.

So,

( X-3) = 0

X = 3

P(X) = X³ -6X² + 6X + k

P(3) = (3)³ - 6 × (3)² + 6 × 3 + K

=> 27 - 6 × 9 + 18 + K

=> 27 - 54 + 18 + K = 0

=> 45 -54 + K = 0

=> K -9 = 0

=> K = 9

HOPE IT WILL HELP YOU....