If x3+ ax2+ 22x-b has (x - 4) as a factor and leaves a remainder 4, when divided
by (x - 3), find a and b.
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Answered by
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P(4)=4^3+a*4^2+22*4-b=0
=>64+16a+88-b=0
=>16a-b=152
P(3)=3^3+a*3^2+22*3-b=4
=27+9a+66-b=4
=>9a-b=4-93
=>9a-b=-89
7a=152+89
a=241/7
use above to find b
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