if x3 +ax2 -bx +10 is divisible by x2 -3x +2,
find values of a and b
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a=2, b=13
Step-by-step explanation:
let, given equation
x²-3x+2 = 0
(x-1)(x-2) = 0
x = 1,2
again
let, p(x) = x³+ax²-bx+10
A/Q,
p(x) is divisible by x²-3x+2
then,
p(1) = 0, and p(2) = 0
Now,
p(1) = 1³+a(1²)-b(1)+10=0
1+a-b+10=0
a-b=-11. (i)
again,
p(2) = 2³+a(2²)-b(2)+10=0
8+4a-2b+10=0
4a-2b=-18
2a-b=-9. (ii)
On solving both the equations,
a=2, and b=13
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