If x⁴ + 2x³ + 8x² +12x +18 is divided by (x² + 5) , remainder comes out to be (px + q) , find values of q and q.
Answers
Answered by
21
Let us divide x⁴ + 2x³ + 8x² +12x +18 by x²+5. The division process is as follows:
x²+5 )x⁴ + 2x³ + 8x² +12x +18(x²+2x+3
x⁴ +5x²
(-) (-)
-------------------------
2x³+3x²+12x +18
2x³ +10x
(-) (-)
---------------------------
3x² +2x+18
3x² +15
(-) (-)
---------------------------
2x + 3
We get the Remainder = 2x + 3
Remainder given= px+q
px+q = 2x + 3
p= 2 , q= 3
[Comparing coefficient of x and constant terms both sides]
Hence, the value of p is 2 & value of q is 3.
HOPE THIS WILL HELP YOU...
x²+5 )x⁴ + 2x³ + 8x² +12x +18(x²+2x+3
x⁴ +5x²
(-) (-)
-------------------------
2x³+3x²+12x +18
2x³ +10x
(-) (-)
---------------------------
3x² +2x+18
3x² +15
(-) (-)
---------------------------
2x + 3
We get the Remainder = 2x + 3
Remainder given= px+q
px+q = 2x + 3
p= 2 , q= 3
[Comparing coefficient of x and constant terms both sides]
Hence, the value of p is 2 & value of q is 3.
HOPE THIS WILL HELP YOU...
Answered by
2
nice Question
remainder is 2x+3
Similar questions
English,
7 months ago
Political Science,
7 months ago
Math,
1 year ago
Chemistry,
1 year ago
Hindi,
1 year ago