Question

if xcosA=3 and 4tanA=y, find relaction between x and y​

Answer 1

Answer:

16x^2-9y^2=144

Step-by-step explanation:

xcosA=3

cosA=3/X

4tanA=y

x^2=3^2+AC^2

AC^2=x^2-9

AC=√x^2-9

tanA=√x^2-9/3

4√x^2-9/3=y

squaring on both sides

16(x^2-9)/9=y^2

16x^2-9y^2=144