If xi 's are the midpoints of the class interval of grouped data , fi 's are the corresponding frequencies and x is the mean then find Σ(fixi - x).
(Class 10 Maths Sample Question Paper)
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Answered by
446
Solution:
Mean (x) = Sum of all the observations/ Number of observations
x = (f1x1 + f2x2 + …..+ fnxn) / f1 + f2 +......+ fn
x = Σfixi / Σfi , Σfi = n
x = Σfixi / n
n x = Σfixi ……………(1)
Σ(fixi - x) = ( f1x1 - x) + ( f2x2 - x)+ …..+(fnxn - x)
Σ(fixi - x) = (f1x1 + f2x2 + …..+ fnxn) - (x +x +....n times)
Σ(fixi - x) = Σfixi -nx
Σ(fixi - x) = nx - nx ( From eq1)
Σ(fixi - x) = 0
HOPE THIS WILL HELP YOU....
Mean (x) = Sum of all the observations/ Number of observations
x = (f1x1 + f2x2 + …..+ fnxn) / f1 + f2 +......+ fn
x = Σfixi / Σfi , Σfi = n
x = Σfixi / n
n x = Σfixi ……………(1)
Σ(fixi - x) = ( f1x1 - x) + ( f2x2 - x)+ …..+(fnxn - x)
Σ(fixi - x) = (f1x1 + f2x2 + …..+ fnxn) - (x +x +....n times)
Σ(fixi - x) = Σfixi -nx
Σ(fixi - x) = nx - nx ( From eq1)
Σ(fixi - x) = 0
HOPE THIS WILL HELP YOU....
Anonymous:
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Answered by
151
Answer: Zero , 0
Step-by-step explanation:
Mean (x) = Sum of all the observations/ Number of observations
x = (f1x1 + f2x2 + …..+ fnxn) / f1 + f2 +......+ fn
x = Σfixi / Σfi , Σfi = n
x = Σfixi / n
n x = Σfixi ……………(1)
Σ(fixi - x) = ( f1x1 - x) + ( f2x2 - x)+ …..+(fnxn - x)
Σ(fixi - x) = (f1x1 + f2x2 + …..+ fnxn) - (x +x +....n times)
Σ(fixi - x) = Σfixi -nx
Σ(fixi - x) = nx - nx ( From eq1)
Σ(fixi - x) = 0
HOPE THIS WILL HELP YOU
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