Question

If xp^2+ x²p - 8 is divided by x - 1, then, remainder is -2, find the values of P. ​

Answer 1

Answer:

The values of p are -3 & 2

Step-by-step explanation:

Let P(x) = xp² + x²p - 8

Since it is divided by (x - 1)

P(1) = remainder . . . . . ( ∵ by remainder thm)

p² + p -8 = -2

p² + p -6 = 0

p² + 3p - 2p - 6 = 0

p(p+3) -2(p+3) = 0

(p+3) (p-2) = 0

p = -3 or. p = 2