If xsecA=1-ytanA and x^2sec^2 A=5+y^2tan^2A then
a)x^2=9y^2/y^2+4
b)x^2=4y^2/9-y^2
c)y^2=4x^2/9+x^2
d)y^2=9x^2/x^2+4
Answers
Answered by
10
Answer:
Ans. a. is. right thanks
Answered by
1
Answer:
OPTION A IS RIGHT
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