Question

If xsq.+1/xsq.=62, find the value of x+1/x​

Answer 1

$Given \:x^{2} + \frac{1}{x^{2}} = 62$

/* Add both sides by 2 , we get */

$\implies x^{2} + \frac{1}{x^{2}} +2= 62+2$

$\implies x^{2} + \frac{1}{x^{2}} +2\times x \times \frac{1}{x} = 64$

$\implies \Big( x + \frac{1}{x}\Big)^{2} = 8^{2}$

$\implies x + \frac{1}{x} = \pm\sqrt{8^{2}}$

$\implies x + \frac{1}{x} = \pm8$

Therefore.,

$\red {x + \frac{1}{x}}\green { = \pm8}$

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