Question

If xy=2 and xy^2=8 what is the value of x

Answer 1

Given that,
xy=8
therefore, x=8/y
and,
xy^2=8
putting the value of x=8/y
8/y*y^2=8
8y=8
y=1
now as we know
xy=8
x*1=8
x=8 ans .

Answer 2

The value of x is $\dfrac{1}{2}$

Step-by-step explanation:

Since we have given that

$xy=2$

and

$xy^2=8$

We need to find the value of 'x'.

So, by dividing, we get that

$\dfrac{xy^2}{xy}=\dfrac{8}{2}\\\\y=4$

So, it becomes

$xy=2\\\\4x=2\\\\x=\dfrac{2}{4}\\\\x=\dfrac{1}{2}$

Hence, the value of x is $\dfrac{1}{2}$

# learn more:

What are the greatest and smallest values that the function f(x, y)=xy takes on the ellipse (x^2)/8+(y^2)/2=1?

https://brainly.in/question/12501410