Question

If xy=6 and (x+y)²= 17 , then the value of x²+y² is ____________ *​

Answer 1

(x+y)^2 = 17

x^2+y^2+2xy=17

x^2+y^2+2×6 =17

because xy =6 as given.

x^2+y^2=17-12=5

Hope this Helps

Answer 2

Answer:

x^2+y^2=5

Step-by-step explanation:

(x+y)^2 =17

x^2+2xy+y^2=17.           (a+b)^2= a^2+b^2+2ab

x^2+y^2+2*6=17.           xy=6

x^2+y^2+12=17

x^2+y^2=17-12

x^2+y^2=5