If xy = 96 and 3y = 2x, then the value of x is
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xy = 96......(1)
3y = 2x ..... (2)
from equation 1 we have,
x = 96/y
substituting the value of x in equation 2
we have
3y = (2 × 96)/y
y^2 = (2×96)/ 3
y^2 = 2× 32
y^2= 64
y= 8
x= 96/y = 96/8
x = 12
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