If y=1/2logx8 then value of x is?
(it is x to the power of 8)
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Given that
y = (logx⁸)/2
⇒ y = 8logx/2 [ using logaⁿ = nloga ]
⇒ y = 4logx
⇒ logx = y/4
Taking anti log, we get
⇒ x = e^(y/4)
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