Question

If Y=(1-2x)(1+x)-2,find the values of X for which Y=-2

Answer 1

Answer:

Given,Y = (1-2x)(1+x)-2

Y = (1+x-2x-2x^2)-2

Y = -2x^2-x-1

Put Y = -2,then

-2 = -2x^2-x-1

2x^2+x+1-2 = 0

2x^2+x-1 = 0

2x^2+2x-x-1 = 0

2x(x+1)-1(x+1) = 0

(x+1)(2x-1)=0

x = -1,1/2