Question

if y=1/3x-1, then dy/dx= ? when x=0​

Answer 1

Answer:

Step-by-step explanation:

Answer 2

$y = \frac{1}{3x - 1}$

$y = {(3x - 1)}^{ - 1}$

$\frac{dy}{dx} = ( - 1) {(3x - 1)}^{ - 2} (3)$

$\frac{dy}{dx} = \frac{ - 3}{ {(3x - 1)}^{2} }$

At x = 0,

$\frac{dy}{dx} = \frac{ - 3}{ {( - 1)}^{2} }$

$\frac{dy}{dx} = - 3 \: .........answer$