Question

If y = 1 is a common root of equations a y square + a y + 3 = 0 and y square + y + b = 0 then find a b

Answer 1

${ay}^{2} + ay + 3 = 0 \\ a \times {1}^{2} + a + 3 = 0 \\ 2a + 3 = 0 \\ a = \frac{ - 3}{2} \\ {ay}^{2} + ay + 3 = 0 \\ a \times {1}^{2} + a \times 1 + b = 0 \\ a + a + b = 0 \\ 2a + b = 0 \\ substituting \: value \: ofa \\ 2 \times \frac{ - 3}{2} + b = 0 \\ - 3 + b = 0 \\ b = 3 \\ hope \: this \: help \: u$