Question

If y + 1 is a factor of y^3 + p, then the value of p is ___

Answer 1

Answer:

The value of p is equal to 1

i.e., p = 1

Step-by-step explanation:

let p(x) = y³ + p

given that, (y +1) is the zero of p(x)

Therefore,

y + 1 = 0

=> y = -1 ----(i)

Now,

Putting the value of y from eq.(i) in p(x), we get,

=> p(x)= y³ + p

=> 0 = (-1)³ + p

=> 0 = (-1)³ + p=> 0 = -1 +p

=> 0 = (-1)³ + p=> 0 = -1 +p=> -p = -1

=> 0 = (-1)³ + p=> 0 = -1 +p=> -p = -1=> p = 1

Hence, The value of p is 1.

Hope this helped..