Question

If y = 1 is a zero of the polynomial q(y) =4y³+ky²-y-1 then find the value of k. ​

Answer 1

Answer:

Given,

4y³+ky²-y-1

-1 is zero Of polynomial

so,

4(-1)³+k(-1)²-(-1)-1=0

4(-1)+k+1-1=0

-4+k=0

k=4

Step-by-step explanation:

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Answer 2

Answer:

Step-by-step explanation:

q(y) = 0 when y=1

Put the value of y, then

4+k+-1-1=0

k= -2