Question

If (y+1) is factor of the 2y²+ky then value of k

Answer 1

Answer:

k = 2

Step-by-step explanation:

If (y+1) is factor of the 2y²+ky then value of k

=> y+1 is a factor

     y+1 = 0

     y = -1

put y = -1,

2(-1)² + k(-1) = 0

2(1) - k = 0

2 - k = 0

  k = 2

Answer 2

Answer:

2

Step-by-step explanation:

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