Question

If y = √(1-x^2) , calculate x when dy/dx = 1

Answer 1

y = √{1 - x²}

diff wrx x

1 = dy/dx = [1/√{1 - x²}] * (-2x)

(-2x) = √{1 - x²}

sbs.

4x² + x² = 1

5x² = 1

x² = 1/5

x = √(1/5)