if (y-1/y)whole cube = 27,then find the value of y cube - 1/y cube.
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Answer:
y^3-(1÷y) ^3=3y^2+27y+3
Step-by-step explanation:
(y-1÷y)^3=27
(a-b) ^3= a^2-b^2-3ab(a-b)
so, (y-1÷y)^3=y^3-(1÷y)^3-3(y)(1÷y)(y-1÷y)
27= y^3-(1÷y)^3-3(y-1÷y)
y^3-(1÷y)^3=27+3y+3÷y
=27y+3y^2+3
=3y^2+27y+3
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