Question

if y^2-1 is a factor of y^4+my^3+2y^2-3y+n find value of m and n​

Answer 1

Answer:

y⁴+my³+2y2-3y+n=0

y²=1

y=±1

put y=1

(1)⁴+m(1)³+2(1)²-3(1)+n=0

1+m+2-3+n=0

m+n=0---1

put y=-1

(-1)⁴+m(-1)³+2(-1)²-3(-1)+n=0

1-m+2+3+n=0

m=6+n

m -n=6---(2)

solve 1 and 2

2m=6

m=3

from eqn(1)

n=-3

so(m,n)=(3,-3)

Answer 2

Step-by-step explanation:

y⁴+my³+2y2-3y+n=0

y²=1

y=±1

put y=1

(1)⁴+m(1)³+2(1)²-3(1)+n=0

1+m+2-3+n=0

m+n=0---1

put y=-1

(-1)⁴+m(-1)³+2(-1)²-3(-1)+n=0

1-m+2+3+n=0

m=6+n

m -n=6---(2)

solve 1 and 2

2m=6

m=3

from eqn(1)

n=-3

so(m,n)=(3,-3)

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