if y^2+1/y^2=23 find the value of y^3+1/y^3
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Here , y^2+1/y^2=23
adding both sides 2 we get:
y^2+2/y^2+2=25
or y^2+1/y^2+2×y×1/y=25
or (y+1/y)^2=25
or y+1/y=root (25)
or, y+1/y=5........ (i)
Now, taking cube both sides of...(i) we get,
y^3+1/y^3+3y+3/y=125
or y^3+1/y^3+3 (y+1/y)=125
or, y^3+1/y^3+3×5 =125 {Using ....(i)}
or, y^3+1/y^3=125-3×5=125-15=110 answer...
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