Question

If y =2/3 is a solutions of 4y²+3ky =, then find the value of k​

Answer 1

Answer:

k = 8/9

Step-by-step explanation:

y = 2/3

4y^2+3ky = 4(2/3)^2+3k(2/3)

= 4×4/8+2k

= 16/9 = 2k

16/9×2 = k

therefore,

k = 8/9

Answer 2

Step-by-step explanation:

hence the value of K is 8/9