if y=2 z=4 find the value of x
z2xy+4xy+qyz=260
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Answered by
1
Answer:
Step-by-step explanation:
Given that
y = 2 and z = 4
z²xy + 4xy + 9yz = 260
( 4 )²x (2 ) + 4x ( 4 ) + 9(2)(4) =260
32x + 16x + 72 = 260
48x = 260- 72
48x = 188
x = 188/48
x = 9/4
Answered by
0
Step-by-step explanation:
y=2 , z=4
z²xy+4xy+4yz=260
4²×x×4+4×x×4+2×4=260
16×x×4+16x+32=260
64x+16x+32=260
80x+32=260
80x=260-32
80x=228
x=228/80
x=2.85
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