If y=2x +4/x +,then x²(d²y)/dx²+x(dy)/dx-y yields
(2) 3
(b) 1
(c)0
(d) 4
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Answered by
12
Answer:
Step-by-step explanation:
y = 2x + 4/x
dy/dx = 2 - 4/x^2
d²y/dx² = 0 + 8/x^3
Now putting in eqn,
x²(d²y)/dx² = x^2 ( 8/x^3 ) = 8/x
x(dy)/dx = x ( 2 - 4/x^2 ) = 2x - 4/x
x²(d²y)/dx²+x(dy)/dx-y = 2x - 4/x + 8/x - 2x - 4/x = 0
Your answer is (c) 0
Hope it helps :-)
Answered by
7
Answer:
The answer is 0
i hope it helps you
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