Question

if y=(2x²+3)³ then find dy/dx at x=-1​

Answer 1

Answer:

y= (2x^2+3)^3

then y= ( 2x^6+ 3×4x^4×3 + 3× 2x^2×9+ 27)

= 2x^6 + 54x^2)

dy/dx= 12x^5+ 108x

=12× -1+ 108×-1

=-120