if y=2x³+4x²-5x+8 find dy/dx
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Answered by
3
GOOD MORNING!!)
F(x) = y = 2x³ + 4x² - 5x + 8
Differentiate both sides with respect to x
F'(x) = 2 d(x³)/dx + 4 d(x²)/dx - 5d(x)/dx
F'(x) = 2 × 3x² + 4 × 2x - 5
F'(x) = 6x² + 8x - 5
NOTE:-
Differentiation of xⁿ with respect to x is
nxⁿ-1
Answered by
2
Answer:
6x^2+8x+5
Step-by-step explanation:
d. (2x^3+4x^2-5x+8)
dx
dy. =d. (2x^3). +d. (4x^2) -d. (5x). +d (8
dx. dx. dx. dx. dx
dy. =6x^2+8x+5+0
dx
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