Question

The charge on 6uF capacitor in the circuit shown is

Answer 1

Answer:

it's answer is 540

Explanation:

from the figure it is clear that all capacitor are connected in parallel.so we know that in parallel, potential will be same.

by the formula,

$charge = capaitor \times potetial$

$q = (6 \times {10}^{ - 6} ) \times 90$

$= 540 \times {10}^{ - 6}$