Math, asked by nirajmaheta2009, 1 year ago

if y=√3√2+√5 then find the value of y^2-2+1/y^2

Answers

Answered by Anonymous
1
y=√6+√5


(y^2 -2 +1 )/ y^2

=(6+5+2√30 -2+1 )/(6+5+2√30)

=(10+2√30)/(11+2√30)

=(10+2√30)×(11-2√30)/(11+2√30)(11-2√30)

=(110+22√30-20√30-120)/ (121-120)

=2√30-10

answer = 2 \sqrt{30}  - 10
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