If y = 3 sin^2 + cos x then dy / dx =
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dy/dx = 6 sin x (cos x) + (-sin x)
dy/ dx = 6 sin x cos x - sin x
(or)
dy / dx = 6 sin x ( cos x - 1) since differentiation of sin x = cos x and differentiation of cos x = - sin x
dy/ dx = 6 sin x cos x - sin x
(or)
dy / dx = 6 sin x ( cos x - 1) since differentiation of sin x = cos x and differentiation of cos x = - sin x
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