Math, asked by kohinakoko53, 1 year ago

If y^3ay^2+6is divisible by y-2 and leaves remainder 3 when divided by y-3 find the value of a and b

Answers

Answered by rajnigandha
0
y-2 can decide y^3ay^2+6
y-2=0
y=2
y^ 3ay^2+6= 0
=2^3a*2^2+6=0
8*a *4+6=0
8*a*10=0
80*a=0
a=0/80=0
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